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How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?
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How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?

User Jens Frandsen
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Standard equation: N2(g)+3H2(g)==>2NH3(g), so through stoichiometry,(3.99 mol N2)(2 mol NH3/1 mol N2)(17.031g of NH3/1 mol NH3), yielding 135.90738g of NH3
User MiDri
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