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How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?

How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?
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How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?

User Jens Frandsen
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Standard equation: N2(g)+3H2(g)==>2NH3(g), so through stoichiometry,(3.99 mol N2)(2 mol NH3/1 mol N2)(17.031g of NH3/1 mol NH3), yielding 135.90738g of NH3
User MiDri
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