Question

QRST is a rectangle. If RT = 5x – 5 and SQ = x + 11, find the value of x.

Answer 1

5x - 5 = x + 11
5x = x + 16
4x = 16
x = 4

Answer 2

Answer: x=4

Explanation:

Given: QRST is a rectangle.

We know that in a rectangle, diagonals are congruent or equal.

Therefore, if QRST is a rectangle.

Then RT=SQ [diagonals of given rectangle]

Now substitute,
`RT=5x-5` and
`SQ = x + 11`, then we have

`5x-5=x+11\\\\\Rightarrow5x-x=11+5\\\\\Rightarrow4x=16\\\\\Rightarrow\ x=4`

Hence, the value of x = 4.