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What is the product of (3y^-4)(2y^-4)?

User Ben Soyka
by
6.1k points

2 Answers

7 votes
(x^a)(x^b)=x^(a+b)

(ab)(cd)=(a)(b)(c)(d)

x^-m=1/(x^m)


(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
2 votes

Answer:

Product of
(3y^(-4))(2y^(-4))=6y^(-8)

Explanation:

Given : Expression
(3y^(-4))(2y^(-4))

To find : The product of the given expression?

Solution :


(3y^(-4))(2y^(-4))

Applying property of exponent,
x^a* x^b=x^(a+b)

Comparing with given expression x=y , a=-4 and b=-4


=(3)*(2)*(y^(-4+(-4)))

Multiply 3 and 2,


=6*(y^(-8))


=6y^(-8)

Therefore, Product of
(3y^(-4))(2y^(-4))=6y^(-8)

User Jenish
by
6.3k points
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