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Let f(x)=(6x^3-7)^3 and g(x)=6x^3-7 Given that f(x)=(h*g)(x), find h(x).

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f(x) = (6x^3 - 7)^3 = h(x) * (6x^3-7)
h(x) = (6x^3-y)^3 / (6x^3-7) = (6x^3 - 7)^2
User Vishvajit Pathak
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