Question

A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its width, w?

2w(2w + 5) = 50
2w(w + 5) = 50
w(2w + 5) = 50
w(w + 5) = 50

Answer 1

The total area will be 50
A=lw
l=2w+5
w(2w+5)=50
Solution: Option 3: w(2w+5)=50

Answer 2

C. w(2w + 5) = 50

Explanation:

Given: A rectangle’s length is 5 inches more than twice its width.

Area (A) = 50 square inches.

Let "l" be the length of the rectangle and "w" be the width of the rectangle.

l = 5 + 2w (5 more than twice its width)

Area of a rectangle A = length * width

Now let's plug in A = 50 and l = 5 + 2w

50 = (5+ 2w)(w)

Which can be written as

w(2w + 5) = 50 [Using the commutative property of addition and multiplication]

Commutative property of addition: a + b = b + a

Commutative property of multiplication: a*b = b*a

The above equation is used to find the value of its width(w)

Therefore, the answer is C. w(2w + 5) = 50