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The two-way frequency table shows data on accidents in the last year for drivers who took a driver safety course. Given that a driver took the safety course, what is the chance that the driver still got in an accident? Round your answer to the nearest whole number.

The two-way frequency table shows data on accidents in the last year for drivers who-example-1
User Pugazh
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Given that the driver had taken the safety course, The answer would be 22
User Logarith
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Answer:

22.4%

Explanation:

We have the events,

A = The driver got in an accident

B = The driver took the safety test

Now, it is required to find the conditional probability P(A|B).

Since,
P(A|B)=(P(A\bigcap B))/(P(B))

From the table, we have that,


P(A\bigcap B)=28\\\\P(B)=125

Thus, we get,


P(A|B)=(28)/(125)

i.e. P(A|B) = 0.224

i.e. P(A|B) = 22.4%

Hence, the probability that the driver got in an accident even though the driver took the safety test is 22.4%

User Jvriesem
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