77.3k views
3 votes
What are the solutions of x2+6x-6=10

User Gadu
by
8.5k points

2 Answers

5 votes
The answer is x= 2, -8
User Martin Bliss
by
8.1k points
1 vote

Answer:


\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}


x=2,\:x=-8

Explanation:

The given expression is
x^(2)+6x-6=10

we need to solve this expression for the value of x


\mathrm{Subtract\:}10\mathrm{\:from\:both\:sides}


\mathrm{Solve\:with\:the\:quadratic\:formula}


\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}


x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)


\mathrm{For\:}\quad a=1,\:b=6,\:c=-16:\quad x_(1,\:2)=(-6\pm √(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1)


x=(-6+√(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1):\quad 2


x=(-6-√(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1):\quad -8


\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}


x=2,\:x=-8

User Sergino
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories