77.2k views
3 votes
What are the solutions of x2+6x-6=10

User Gadu
by
6.5k points

2 Answers

5 votes
The answer is x= 2, -8
User Martin Bliss
by
6.0k points
1 vote

Answer:


\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}


x=2,\:x=-8

Explanation:

The given expression is
x^(2)+6x-6=10

we need to solve this expression for the value of x


\mathrm{Subtract\:}10\mathrm{\:from\:both\:sides}


\mathrm{Solve\:with\:the\:quadratic\:formula}


\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}


x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)


\mathrm{For\:}\quad a=1,\:b=6,\:c=-16:\quad x_(1,\:2)=(-6\pm √(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1)


x=(-6+√(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1):\quad 2


x=(-6-√(6^2-4\cdot \:1\left(-16\right)))/(2\cdot \:1):\quad -8


\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}


x=2,\:x=-8

User Sergino
by
5.7k points