ANSWER
25 N
Step-by-step explanation
Given:
• The spring constant, k = 75 N/m
,
• The distance the spring is stretched, x = 0.333 m
Find:
• The ,weight, that hangs from the spring, Fg
If we draw a free-body diagram for this situation, we can see that the forces acting on the mass hanging from the spring are the spring force and its weight,
If the weight hangs motionless, it means that it is in equilibrium and the two forces are equal and opposite,
So the weight is equal to the spring force,
Hence, the weight is 25 N.