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Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.

User Tglas
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The first thing I'd do is put this equation into standard slope - intercept form.

12x - 5y = 2 Subtract 12x from each side
-5y = -12x + 2 Divide each side by -5 to isolate the y
y = 12/5(x) - 2/5

The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b Fill in the variables
3 = 12/5(2) + b Simplify
3 = 24/5 + b Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer.

y = 12/5x - 9/5
User Seorphates
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