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max is making a rectangular garden that is 5 feet less than twice its width. If the perimeter of the garden is 80 feet, what will be its dimensions?

2 Answers

5 votes
l=2w-5

2(l+w)=80
l+w=40
2w-5+w=40
3w=45
w=15 feet
l=25 feet. As a result, the width is 15 feet and length is 25 feet. Hope it help!
User Fry
by
8.0k points
2 votes

Answer:

Length = 25 feet and width = 15 feet

Explanation:

MAx is making a rectangular garden that is 5 feet less than twice its width

LEt w be the width of the garden.

Length is 5 feet less than twice its width

So length of the garden =
2w-5

Perimeter of the garden is 80 feet

Perimeter of rectangle =
2(length ) + 2(width)


80=2(2w-5) + 2(w), solve for w


80=4w-10 + 2(w)


80=6w-10

Add 10 on both sides


90=6w, divide both sides by 6

w=15


L=2w-5=2(15)-5= 30-5=25

So Length = 25 feet and width = 15 feet

User Cadetill
by
7.9k points

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