Question

max is making a rectangular garden that is 5 feet less than twice its width. If the perimeter of the garden is 80 feet, what will be its dimensions?

Answer 1

l=2w-5

2(l+w)=80
l+w=40
2w-5+w=40
3w=45
w=15 feet
l=25 feet. As a result, the width is 15 feet and length is 25 feet. Hope it help!

Answer 2

Length = 25 feet and width = 15 feet

Explanation:

MAx is making a rectangular garden that is 5 feet less than twice its width

LEt w be the width of the garden.

Length is 5 feet less than twice its width

So length of the garden =
`2w-5`

Perimeter of the garden is 80 feet

Perimeter of rectangle =
`2(length ) + 2(width)`

`80=2(2w-5) + 2(w)`, solve for w

`80=4w-10 + 2(w)`

`80=6w-10`

Add 10 on both sides

`90=6w`, divide both sides by 6

w=15

`L=2w-5=2(15)-5= 30-5=25`

So Length = 25 feet and width = 15 feet