Question

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).

The reaction is at equilibrium at 1,000 K. The equilibrium constant of the reaction is 3.90. At equilibrium, the concentrations are as follows.

[CO] = 0.30 M
[H2] = 0.10 M
[H2O] = 0.020 M

What is the equilibrium concentration of CH4 expressed in scientific notation?

Answer 1

The equilibrium concentration of CH$ expressed in scientific notation should be
5.9 x 10^-2

hope this helps :)

Answer 2

Answer: The equilibrium concentration of
`CH_4` in scientific notation is
`5.85* 10^(-2)M`

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_(eq)`

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

`CO+3H_2\rightleftharpoons H_2O+CH_4`

The expression for the
`K_(eq)` is given as:

`K_(eq)=([CH_4][H_2O])/([CO][H_2]^3)`

We are given:

`[CO]=0.30M`

`[H_2]=0.10M`

`[H_2O]=0.020M`

`K_(eq)=3.90`

Putting values in above equation, we get:

`3.90=([CH_4]* 0.020)/(0.30* (0.10)^3)`

`[CH_4]=0.0585M=5.85* 10^(-2)M`

Hence, the equilibrium concentration of
`CH_4` in scientific notation is
`5.85* 10^(-2)M`