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The equation of the circle whose center is at (3, 7) and whose radius is 6 is

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the eqn is (x-3)^2+(y-7)^2=36.
User MauMen
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3 votes

Answer:


(x-3)^2+(y-7)^2=36

Explanation:

We are asked to find the equation of the circle whose center is at (3, 7) and whose radius is 6.

We know that standard equation of circle is in form
(x-h)^2+(y-k)^2=r^2, where,

(h,k) = Center of circle,

r = Radius of circle.

Upon substituting our given values in above formula we will get,


(x-3)^2+(y-7)^2=6^2


(x-3)^2+(y-7)^2=36

Therefore, the equation of our given circle would be
(x-3)^2+(y-7)^2=36.

User Mertuarez
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