Question

The equation of the circle whose center is at (3, 7) and whose radius is 6 is

Answer 1

the eqn is (x-3)^2+(y-7)^2=36.

Answer 2

`(x-3)^2+(y-7)^2=36`

Explanation:

We are asked to find the equation of the circle whose center is at (3, 7) and whose radius is 6.

We know that standard equation of circle is in form
`(x-h)^2+(y-k)^2=r^2`, where,

(h,k) = Center of circle,

r = Radius of circle.

Upon substituting our given values in above formula we will get,

`(x-3)^2+(y-7)^2=6^2`

`(x-3)^2+(y-7)^2=36`

Therefore, the equation of our given circle would be
`(x-3)^2+(y-7)^2=36`.