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The equation ㏒3(2x+p) = 2㏒3(2x) - 1 has one real root. What is the value of p? (if you could explain it please but I got x=(6+-√(36+48p) )/(8) )

The equation ㏒3(2x+p) = 2㏒3(2x) - 1 has one real root. What is the value of p? (if you could explain it please but I got x=(6+-√(36+48p) )/(8) )
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The equation ㏒3(2x+p) = 2㏒3(2x) - 1 has one real root. What is the value of p?

(if you could explain it please but I got x=
(6+-√(36+48p) )/(8) )

User Sixto
by
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1 Answer

2 votes

Answer:zero 9

Explanation:

User Unniverzal
by
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