Question

20 POINTS!!!!!!

When a certain metal is illuminated with light of frequency 3.1 ✕ 1015 Hz, a stopping potential of 6.6 V is required to stop the most energetic ejected electrons. What is the work function of this metal?

Answer= Ev

Answer 1

The ejected electrons have a kinetic energy of 10 eV.
The incoming photons have an energy
E = h f = 3.008 10^(-18) J = 18.776 eV
The work function is the difference between those two: 8.776 eV

hope it helps

Answer 2

The ejected electrons have a kinetic energy of 10 eV.
The incoming photons have an energy
E = h f = 3.008 10^(-18) J = 18.776 eV
The work function is the difference between those two: 8.776 eV