25.8k views
11 votes
A rectangle has a length of x and a width of 5x cubed+4-x squared. Find the perimeter of the rectangle when the length is 5 feet

1 Answer

11 votes

Answer:

1060 feet

Explanation:

The computation of the perimeter of the rectangle is as follows;

As we know that

Perimeter of the rectangle = 2 × ( length + width)

where

Length of x = 5

And, the width be 5x^3 - 4x^2

= 5(5)^3 - 4(5)^2

= 625 - 100

= 525

Now the perimter is

= 2 × (5 + 525)

= 1060 feet

User Djwbrown
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories