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A rectangle has a length of x and a width of 5x cubed+4-x squared. Find the perimeter of the rectangle when the length is 5 feet

1 Answer

11 votes

Answer:

1060 feet

Explanation:

The computation of the perimeter of the rectangle is as follows;

As we know that

Perimeter of the rectangle = 2 × ( length + width)

where

Length of x = 5

And, the width be 5x^3 - 4x^2

= 5(5)^3 - 4(5)^2

= 625 - 100

= 525

Now the perimter is

= 2 × (5 + 525)

= 1060 feet

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