163k views
3 votes
How many solutions does the system have?

{y=−2x+2
{y=x^2−3x



Enter your answer in the box

2 Answers

5 votes
If a solution(s) exists y=y so we can say:

x^2-3x=-2x+2 add 2x to both sides

x^2-x=2 subtract 2 from both sides

x^2-x-2=0 factor

(x-2)(x+1)=0

So x=-1 and 2, using y=-2x+2 we find:

y(-1)=4 and y(2)=-2

So the two solutions occur at the points:

(-1,4) and (2,-2)
User Aibrean
by
9.1k points
4 votes

Answer:it has 2 solutions

Step-by-step explanation: Just took the quiz

How many solutions does the system have? {y=−2x+2 {y=x^2−3x Enter your answer in the-example-1
User Shadit
by
8.7k points

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