Question

How many solutions does the system have?

{y=−2x+2
{y=x^2−3x



Enter your answer in the box

Answer 1

If a solution(s) exists y=y so we can say:

x^2-3x=-2x+2 add 2x to both sides

x^2-x=2 subtract 2 from both sides

x^2-x-2=0 factor

(x-2)(x+1)=0

So x=-1 and 2, using y=-2x+2 we find:

y(-1)=4 and y(2)=-2

So the two solutions occur at the points:

(-1,4) and (2,-2)

Answer 2

Answer:it has 2 solutions

Step-by-step explanation: Just took the quiz