Answer: The answer is (A). Similar.
Step-by-step explanation: We are given two triangles, ΔABC and ΔDEF where, ∠B = 80°, ∠C = 60°, ∠D = 40° and ∠E = 80°.
We are to check whether the two triangles are similar or not.
In ΔABC, we have

and in ΔDEF, we have

Therefore, in ΔABC and ΔDEF, we have
∠A = ∠D,
∠B = ∠E,
∠C = ∠F.
So, by AAA similarity postulate, we get
ΔABC ≈ ΔDEF.
Thus, (A) is the correct option.