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what number is four less than 3 times a second number is three more than twice the first number is decreased by twice a second the result is 11 find both numbers

User Yam Tal
by
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1 Answer

20 votes
20 votes

Given

Let x: one number

Let y: second number

Procedure

what number is four less than 3 times a second number

x = 3y - 4

three more than twice the first number is decreased by twice a second the result is 11

2x + 3 - 2y = 11

2x - 2y = 11 - 3

2x - 2y = 8

Replace x with (3y-4) from the 1st statement, and solve for y

2(3y - 4) - 2y = 8

6y - 8 - 2y = 8

4y = 8 + 8

4y = 16

y = 16/4

y = 4

Now for x,

x = 3(4) - 4

x = 12 - 4

x = 8

The answer would be x = 8 and y = 4

User Antoine Subit
by
2.8k points
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