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Find the slope of the line that passes through the pair of points.(- 42.75,5.7) and (2.75, 4.1)Note: It didn't provide a graph or anything.The slope is __

User Matt Koskela
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1 Answer

23 votes
23 votes

A line equation can be written in slope-intercept form. The slope-intercept form is


y=mx+b

Where m represents the slope and b the y-intercept.

We can substitute our points on this form to get a system of equations to find the slope and y-intercept of our desired line. Using the points (- 42.75, 5.7) and (2.75, 4.1), we have


\begin{cases}5.7=-42.75m+b \\ 4.1=2.75m+b\end{cases}

If we subtract the second equation from the first equation, we get a new equation only for the slope.


\begin{gathered} 5.7-(4.1)=-42.75m+b-(2.75m+b) \\ 1.6=-45.5m \\ m=-(1.6)/(45.5) \end{gathered}

And this is our slope.

User Steve Ward
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2.9k points