Question

Suppose a binomial event has a probability of success of 0.3, and 1250 trials are performed. What is the standard deviation of the possible outcomes? Round your answer to two decimal places.

Answer 1

`√(1250*0.3*(1-0.3))\approx16.20`

Answer 2

Answer: 16.20

Explanation:

For any binomial event , the formula to calculate the standard deviation of the possible outcomes is given by :-

`\sigma=\sqrt{\text{p(1-p)n}}`

Given: The probability of success p = 0.3

Then , the probability of failure q= 1-0.3=0.7

Now, by using above formula , the standard deviation of the possible outcomes will be :-

`\sigma=√(0.3*0.7*1250)\\\\\Rightarrow\sigma=√(262.5)\\\\\Rightarrrow\sigma=16.201851746\approx16.20`

Hence, the standard deviation of the possible outcomes = 16.20