Question

Write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3)

A) y = –5x – 27
B) y = –5x + 27
C) y = 5x – 9
D) y = –5x + 9

Answer 1

You would need a new y-intercept in order for this to be parallel. So you use the points given and the slope and fill it in. 3=-5(-6)+b. 3=30+b. Then subtract 30 from both sides. -27=b. Then just put it all back into slope intercept form. y=-5x-27.

Answer 2

Explanation:

y = –5x + 3

slope of the given line by comparing with y=mx+b is

m= - 5

Concept is that the slope of parallel lines are equal so we need a line with slope same as m=-5

and passes through point (-6,3)

Equation using the point slope equation

y-3 = -5 (x-(-6))

y-3=-5(x+6)

y-3= -5x-30

y= -5x -27

A