Question

A line passes through (–7, –5) and (–5, 4).Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers.

A) y + 5 = 9/2x – 7); –9x + 2y = 53
B) y + 5 = 9/2(x + 7); –9x + 2y = 53
C) y – 5 = 9/2(x + 7); –9x + 2y = –53
D)y + 7 = 9/2(x + 5); –9x + 2y = 31

Answer 1

B) y+5=9/2(x+7);-9x+2y=53

Answer 2

Option B is correct.

Explanation:

We have been given the points (-7,-5) and (-5,4)

We have an equation for point-slope form:

`y-y_1=(y_2-y_1)/(x_2-x_1)\cdot (x-x_1)`

Here,
`x_1=-7,y_1=-5,x_2=-5,y_2=4`

On substituting the values in the formula:

`y-(-5)=(4-(-5))/(-5-(-7))\cdot (x-(-7))`

`\Rightarrow y+5=(9)/(2)\cdot (x+7)`

`\Rightarrow 2y+10= 9\cdot (x+7)`

`\Rightarrow -9x+2y=53`

Therefore, Option B is correct.