Question

Solve for squar root of 3x+12=x

Answer 1

assuming

`√(3x+12) =x`
sqare both sides
3x+12=x²
minus 3x+12 both sides
x²-3x-12=0
factor
we can't
use quadratic formula
for
ax²+bx+c=0

`x= (-b+/- √(b^2-4ac) )/(2a)`
so


`x= (-(-3)+/- √((-3)^2-4(1)(-12)) )/(2(1))`
simplfying we get

`x= (3+ √(57) )/(2)` or
`x= (3- √(57) )/(2)`