A total of 6 family members will appear in a portrait. If 3 of the family members may sit in the front row, how many combinations of family members may sit in the front row?

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asked Jun 7, 2018 151k views

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JPetric · Answer 1 · 2018-06-13T03:32:30+0000

Basically, it is asking in how many ways can you choose 3 people out of a set of six.

combinations = n! / (r! * (n-r)!)
combinations = 6! / 3! * 3!
combinations = 6 * 5 * 4 / 3!
combinations = 20

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A total of 6 family members will appear in a portrait. If 3 of the family members may sit in the front row, how many combinations of family members may sit in the front row?

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