Question

Y=x^2-12x+45 vertex form and coordinate vertex

Answer 1

To write the given quadratic equation, y = x^2-12x+45, in vertex form, complete the square to find the values of h and k. The vertex form is y = (x-6)^2 + 9, and the vertex of the parabola is (6, 9).

Step-by-step explanation:

To write the given quadratic equation, y = x^2-12x+45, in vertex form, we need to complete the square. The vertex form of a quadratic equation is given by y = a(x-h)^2 + k, where (h, k) represents the vertex of the parabola. In this case, a = 1, so let's find the values of h and k.

Step 1: Factor out the coefficient of x^2, which is 1.

y = 1(x^2 - 12x) + 45

Step 2: Complete the square by adding and subtracting the square of half the coefficient of x, which is (-12/2)^2 = 36.

y = 1(x^2 - 12x + 36 - 36) + 45

Step 3: Rewrite the equation by grouping the perfect square trinomial and the constant term.

y = 1[(x-6)^2 - 36] + 45

Step 4: Simplify the equation.

y = (x-6)^2 - 36 + 45

y = (x-6)^2 + 9

So, the vertex form of the given equation is y = (x-6)^2 + 9. The vertex of the parabola is (6, 9).

Answer 2

Best Answer

x2-12x-45=0 Two solutions were found : x = 15 x = -3Step by step solution :Step 1 :Skip Ad
Trying to factor by splitting the middle term 1.1 Factoring x2-12x-45

The first term is, x2 its coefficient is 1 .
The middle term is, -12x its coefficient is -12 .
The last term, "the constant", is -45

Step-1 : Multiply the coefficient of the first term by the constant 1 • -45 = -45

Step-2 : Find two factors of -45 whose sum equals the coefficient of the middle term, which is -12 .
-45 + 1 = -44 -15 + 3 = -12 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 3
x2 - 15x + 3x - 45

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-15)
Add up the last 2 terms, pulling out common factors :
3 • (x-15)
Step-5 : Add up the four terms of step 4 :
(x+3) • (x-15)
Which is the desired factorizationEquation at the end of step 1 : (x + 3) • (x - 15) = 0 Step 2 :Theory - Roots of a product : 2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.Solving a Single Variable Equation : 2.2 Solve : x+3 = 0

Subtract 3 from both sides of the equation :
x = -3
Solving a Single Variable Equation : 2.3 Solve : x-15 = 0

Add 15 to both sides of the equation :
x = 15
Supplement : Solving Quadratic Equation DirectlySolving x2-12x-45 = 0 directly Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic FormulaParabola, Finding the Vertex : 3.1 Find the Vertex of y = x2-12x-45

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 6.0000

Plugging into the parabola formula 6.0000 for x we can calculate the y -coordinate :
y = 1.0 * 6.00 * 6.00 - 12.0 * 6.00 - 45.0
or y = -81.000Parabola, Graphing Vertex and X-Intercepts :Root plot for : y = x2-12x-45
Axis of Symmetry (dashed) {x}={ 6.00}
Vertex at {x,y} = { 6.00,-81.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-3.00, 0.00}
Root 2 at {x,y} = {15.00, 0.00}