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If 0.091 M of KF has a volume of 113.6 mL. what mass of KF is in the solution
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If 0.091 M of KF has a volume of 113.6 mL. what mass of KF is in the solution

User Mihkov
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hey there

That's easy

Molarity=moles/L

0.091M=x/0.1136L
x=0.091*0.1136
x=0.0103 moles

1 mole of KF=58.0967
0.0103 moles of KF=0.6 g

Hope this helps

User Mangaldeep Pannu
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