1. An isosceles triangle has two angles that are equal
so if angle A is 40°
Let the other two angles be 2x
2x + 40 = 180° (sum of angle in a triangle)
solve for x
2x + 40° = 180°
subtract 40° from both-side of the equation
2x = 180° - 40°
2x = 140°
Divide both-side of the equation by 2
x = 70°
There the possible measures for;
angle B = 70°
angle C = 70°
2.
In a right-angle triangle,
One of the angle must be 90°
angle A=40°
Let angle B = 90°
we will now find angle C
40° + 90° + C = 180° (sum of angle in a triangle)
solve for C
130° + C = 180°
subtract 130° from both-side of the equation
C = 180° - 130°
C=50°
The possible value of;
angle B=90°
angle C = 50°