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What is the area of a sectorwhen r:5/6and 0=2/3 radians?

What is the area of a sectorwhen r:5/6and 0=2/3 radians?-example-1
User Valentine
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1 Answer

25 votes
25 votes

Given:

Radius = 5/6

Angle


\theta=(2\pi)/(3)\text{ radians}

Required:

Find the area of the sector.

Step-by-step explanation:

The area of the sector is given by the formula:


A=(1)/(2)r^2\theta

Substitute the given values in the formula.


\begin{gathered} A=(1)/(2)*((5)/(6))^2*(2\pi)/(3) \\ =(1)/(2)*(25)/(36)*(2\pi)/(3) \\ =(25\pi)/(108)\text{ sq unit} \end{gathered}

Final Answer:

Thus the area of the sector is


(25\pi)/(108)

User Novalis
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