Question

One mole of propane (44 grams) reacts with 5 moles of oxygen to produce 2220 kJ of heat. How many grams of propane would produce 6660 kJ of heat? A.220 g B. 132 g C. 4440 g D.49 g

Answer 1

i feel like the answer is B

Answer 2

The correct answer is option B.

132 grams of propane would produce 6660 kJ of heat.

Step-by-step explanation:

Step-by-step explanation:

`C_3H_8+5O_2\rightarow 3CO_2+4H_2O,\Delta H=-2,220 kJ`

According to chemical reaction, combustion of 1 mole of propane gives 2,220 kilo Joules of heat , then 6,660 Kilo joules of heat will be obtained from :

`(1)/(-2,220)* (-6,660 mol)=3.000 mol`

Mass of 3.000 moles of propane :

3.000 mol × 44 g/mol = 132 g

132 grams of propane would produce 6660 kJ of heat.