Question

1. Find the perimeter of the triangle with coordinates A (1, 2), B( 6, 5), and C (1, 7)

Answer 1

The perimeter is just the sum of all side lengths. Here we have sides AB, BC, and AC.

The side lengths are found using the pythagorean theorem...

d^2=(dx)^2+(dy)^2

AB^2=5^2+3^2=34, AB=√34

BC^2=5^2+2^2=29, BC=√29

AC^2=0^2+5^2=25, AC=√25

So the perimeter is:

P=√34+√29+√25

P≈16.22 units (to the nearest hundredth of a unit)