The function y = h(x) is defined as follows: (picture of question shown)

Question

asked May 22, 2018 138k views

2 Answers

Dinomix · Answer 1 · 2018-05-26T22:34:14+0000

Answer:

h(1)=1 and
h(4)=5

Explanation:

We are given the function,

$h(x)=\left\{\begin{matrix}x^2,&x<0\\3-x,&0\leq x<1\\x^2,&1\leq x\leq 3\\5,&x>3\end{matrix}\right.$

Since, when x= 1, the function is
h(x)=x^2

Then,
h(1)=(1)^2= 1

Also, when x= 4, the function is
h(x)=5

That is,
h(4)=5

Hence, we get that,

h(1)=1

h(4)=5