Question

The function y = h(x) is defined as follows: (picture of question shown)

Answer 1

h(1)= (1)^3= 1
H(4) =5

Answer 2

`h(1)=1` and
`h(4)=5`

Explanation:

We are given the function,

`h(x)=\left\{\begin{matrix}x^2,&x<0\\3-x,&0\leq x<1\\x^2,&1\leq x\leq 3\\5,&x>3\end{matrix}\right.`

Since, when x= 1, the function is
`h(x)=x^2`

Then,
`h(1)=(1)^2= 1`

Also, when x= 4, the function is
`h(x)=5`

That is,
`h(4)=5`

Hence, we get that,

`h(1)=1`

`h(4)=5`