We need to find the equation of the line that is parallel to y = -2 and passes through (2, 6).
The line given, y = -2, is a horizontal line.
Horizontal lines are of the form y = a.
Now,
The point (x,y) is (2,6).
Since we need a line parallel, it will also be a horizontal line of the form y = a, where a is the y coordinate of the coordinate pair given.
Hence, the parallel line will be:
y = 6