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Given the function j(x) = x^2 +3x -4 match the description with the critical point

Given the function j(x) = x^2 +3x -4 match the description with the critical point-example-1
User ProtoEvangelion
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1 Answer

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8 votes

The y-intercept is where the function crosses the y-axis (x=0)

(0,-4)

j(x) = x^2 +3x -4

j(0) = 0+0-4

j(0=-4

The x-intercept is where the function crosses the x-axis (y=0)

(-4,0)

The axis of symmetry x is where the function has symmetry (see graph attached)

The axis of symmetry is x = 1.5

And finally, the minimum y is -6.25 (also seeing the graph, the lowest value of y)

Given the function j(x) = x^2 +3x -4 match the description with the critical point-example-1
User Fahim Babar Patel
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