Question

At STP what is the volume of 16.34 grams of nitrogen gas?

Answer 1

Answer:

Volume = 13.06 L

Step-by-step explanation:

We are given: mass of nitrogren gas = 16.34 g

We know: molar mass of nitrogen gas = 28.014 g/mol

: ideal gas law constant = 0.082 L.atm/K.mol

At STP: temperature = 273.15 K

: pressure = 1 atm

We first determine the number of moles of nitrogen gas:

n = m/M

= 16.34/28.014

= 0.58 mol

Using the ideal gas law:

`\begin{gathered} PV\text{ = nRT} \\ \\ \therefore V\text{ = }(nRT)/(P)\text{ = }(0.58*0.082*273.15)/(1)\text{ = 13.06 L} \end{gathered}`