Question

Find the equation (in terms of x) of the line through the points (-3,-3) and (4,-2) II

Answer 1

Given:

The coordinates of the points through which the line passes,

(x1, y1)=(-3, -3).

(x2, y2)=(4, -2).

The two point form of the equation of a line can be expressed as,

`y-y1=(y2-y1)/(x2-x1)(x-x1)`

Substitute the known values in the above equation.

`\begin{gathered} y-(-3)=(-2-(-3))/(4-(-3))(x-(-3)) \\ y+3=(-2+3)/(4+3)(x+3) \\ y+3=(1)/(7)(x+3) \\ 7(y+3)=x+3 \\ 7y+7*3=x+3 \\ 7y+21=x+3 \\ 7y=x+3-21 \\ 7y=x-18 \\ y=(1)/(7)x-(18)/(7) \end{gathered}`

Therefore, the equation of the line is,

`y=(1)/(7)x-(18)/(7)`