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4 votes
Given: tangent to Circle O. If m C = 57°, then m BDR =

A 57
B 90
C 114

Given: tangent to Circle O. If m C = 57°, then m BDR = A 57 B 90 C 114-example-1

2 Answers

4 votes
∠BCD = 57°
∴ ∠BDR = ∠BCD = 57° (angle that meets the chord and the tangent is equi-angular to the angle at the alternate segment)
User SyntaxVoid
by
6.6k points
6 votes

Answer:

The correct option is A.

Explanation:

Given information: O is the center of the circle, and measure of angle C is 57°.

Alternate segment theorem: According to the alternate segment theorem an angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.

Line RD is tangent to the circle at point D.

Using alternate interior theorem,


\angle BRD=\angle BCD


\angle BRD=57^(\circ)
[\because C=57^(\circ)]

Therefore option A is correct.

User Ricky Ponting
by
6.8k points
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