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A vector of components (6, 2) is multiplied by the scalar value of 3. What is the magnitude and direction of the resultant vector? magnitude: 19.0; direction: 18.4° magnitude: 8.49; direction: 45.0° magnitude: 2.11; direction: 12.6° magnitude: 18.1; direction: 16.7°

User DotchuZ
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2 Answers

2 votes
you don't have 12.6 in there
User Yorkwar
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Answer: The magnitude and direction of the vector with component (6, 2) after multiplication with scalar value 3 is:

magnitude: 19.0; direction: 18.4°

Explanation;


\overrightarrow{V}=6\widehat{i}+2\widehat{j}


|\overrightarrow{V}|=√(6^2+2^2)=2√(10)


\overrightarrow{V}=3* |\overrightarrow{V}|=3* 2sqrt{10}=18.97\approx 19

Direction:
\tan\theta =(2)/(6)p


\theta =\tan^(-1)(1)/(3)=18.43^o\approx 18.4^o

The magnitude and direction of the vector with component (6, 2) after multiplication with scalar value 3 is:

magnitude: 19.0; direction: 18.4°

User Posdef
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