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2 votes
Solve x3 = 64 over 27.

User Jeannot
by
8.5k points

2 Answers

5 votes
x3=64
x=21,3
.....................
User Joeann
by
9.2k points
4 votes
assuming yo meant

x^3= (64)/(27)
reemmeber

\sqrt{ (x)/(y) } = ( √(x) )/( √(y) )

so

x^3= (64)/(27)
cube root both sides

x= \sqrt[3]{ (64)/(27)}

x= \frac{ \sqrt[3]{64} }{ \sqrt[3]{27} }

x= (4)/(3)
User Nyks
by
7.8k points

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