By conics I'm assuming you mean ellipses and hyperbolas:
Ellipses:
((X^2)/16)+((y^2)/9)=1
This would give you a center at 0,0 ; and the ellipse would stretch 4 units in each x direction and 3 units in each y direction (4 form the root of 16, and 3 from the root of 9). This would give you an oval shape.
Hyperbolas:
(Practically the same thing, only instead of adding the two fraction, you subtract; which makes sense because in ellipses, the two portions connect to make an oval, while in hyperbolas, the spread away from each other)
((X^2)/16)-((y^2)/9)=1
This would give you a guide point at 0,0 ; and the hyperbola's sides would start 4 units away from the center. The asymptotes for the hyperbola would be y=+-3/4
Graphing (and describing how to graph) hyperbolas is hard to do; but I hope this helps in he slightest.