Question

Guys, I really need that help T-T.

The side lengths of a triangle are 5,√3,√28. Is the triangle a right triangle? How would I solve this?

Answer 1

First to Answer:

The triangle would be a cute Scalene Triangle!

Here's all that you really can do with solving that

√28 =5.29150262213

√8 = 2.82842712475

Side a = 2.8

Side b = 5

Side c = 5.2

Angle ∠A = 31.788° = 31°47'18" = 0.55481 rad

Angle ∠B = 70.167° = 70°10'0" = 1.22464 rad

Angle ∠C = 78.045° = 78°2'42" = 1.36214 rad

Area = 6.84817

Perimeter p = 13

Semiperimeter s = 6.5

Height ha = 4.89155

Height hb = 2.73927

Height hc = 2.63391

Median ma = 4.9051

Median mb = 3.34515

Median mc = 3.10805

Inradius r = 1.05357

Circumradius R = 2.65764

Vertex coordinates: A[0, 0] B[5.2, 0] C[4.25, 2.63391]

Centroid: [3.15, 0.87797]

Inscribed Circle Center: [3.7, 1.05357]

Circumscribed Circle Center: [2.6, 0.55051]

Answer 2

I’m not good at explaining but I’ll try.

Legs: 5, √3. Hypotenuse: √28

So your legs are: a and b, and ur hypotenuse is c

a^2+b^2=c^2
Which means

5^2+√3 has to equal to √28^2.

Let’s solve it

5^2+√3^2= √28^2

= 25+3=28

28=28

So that is a right triangle.