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Evaluate the sum of the finite geometric series. 1+2+4+8+...+128
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Evaluate the sum of the finite geometric series.
1+2+4+8+...+128

User J Steven Perry
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1 Answer

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S = a*((1 - r^(n+1))/(1-r)) S = 1*((1 - 2^(7+1))/(1-2)) S = 1*((1 - 2^8)/(1-2)) S = 1*((1 - 256)/(1-2)) S = 1*((-255)/(-1)) S = 255 So 1+2+4+8+...+128 = 255
User Anjana Sharma
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