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Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth
asked
Dec 9, 2018
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Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth
Mathematics
middle-school
Akilan
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Answer:
The answer is 26CM
Explanation:
Gaurav Navgire
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Dec 11, 2018
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Gaurav Navgire
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A=2pr^2+2prh and r=d/2 so
A=(2pd^2)/4+(2pdh)/2
A=(2pd^2+4pdh)/4
A=(2pd/4)(d+2h)
A=(pd/2)(d+2h)
A=(6p/2)(6+2*50)
A=(3p)(106)
A=318p cm^2
A≈999.0 cm^2 (to nearest tenth of a square centimeter)
Rpax
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Dec 13, 2018
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Rpax
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