Question

Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth

Answer 1

The answer is 26CM

Explanation:

Answer 2

A=2pr^2+2prh and r=d/2 so

A=(2pd^2)/4+(2pdh)/2

A=(2pd^2+4pdh)/4

A=(2pd/4)(d+2h)

A=(pd/2)(d+2h)

A=(6p/2)(6+2*50)

A=(3p)(106)

A=318p cm^2

A≈999.0 cm^2 (to nearest tenth of a square centimeter)